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Indefinite Integrals question

2024 · 27 Jan · Shift 2 · Q47
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  5. /2024 · 27 Jan · Shift 2 · Q47

Indefinite Integrals question

2024 · 27 Jan · Shift 2 · Q47

JEE MainMathematicsIndefinite IntegralsMCQ+4 / −1
 The integral ∫(x8−x2)dx(x12+3x6+1)tan⁡−1(x3+1x3) is equal to : \text { The integral } \int \frac{\left(x^8-x^2\right) \mathrm{d} x}{\left(x^{12}+3 x^6+1\right) \tan ^{-1}\left(x^3+\frac{1}{x^3}\right)} \text { is equal to : } The integral ∫(x12+3x6+1)tan−1(x3+x31​)(x8−x2)dx​ is equal to : 
  1. A
    log⁡e(∣tan⁡−1(x3+1x3)∣)1/3+C\log _{\mathrm{e}}\left(\left|\tan ^{-1}\left(x^3+\frac{1}{x^3}\right)\right|\right)^{1 / 3}+\mathrm{C}loge​(​tan−1(x3+x31​)​)1/3+C
  2. B
    log⁡e(∣tan⁡−1(x3+1x3)∣)+C\log _{\mathrm{e}}\left(\left|\tan ^{-1}\left(x^3+\frac{1}{x^3}\right)\right|\right)+\mathrm{C}loge​(​tan−1(x3+x31​)​)+C
  3. C
    log⁡e(∣tan⁡−1(x3+1x3)∣)1/2+C\log _{\mathrm{e}}\left(\left|\tan ^{-1}\left(x^3+\frac{1}{x^3}\right)\right|\right)^{1 / 2}+\mathrm{C}loge​(​tan−1(x3+x31​)​)1/2+C
  4. D
    log⁡e(∣tan⁡−1(x3+1x3)∣)3+C\log _{\mathrm{e}}\left(\left|\tan ^{-1}\left(x^3+\frac{1}{x^3}\right)\right|\right)^3+\mathrm{C}loge​(​tan−1(x3+x31​)​)3+C
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