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Indefinite Integrals question

2019 · 10 Apr · Shift 1 · Q38
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Indefinite Integrals question

2019 · 10 Apr · Shift 1 · Q38

JEE MainMathematicsIndefinite IntegralsMCQ+4 / −1
If ∫dx(x2−2x+10)2=A(tan⁡−1(x−13)+f(x)x2−2x+10)+C\int {{{dx} \over {{{\left( {{x^2} - 2x + 10} \right)}^2}}}} = A\left( {{{\tan }^{ - 1}}\left( {{{x - 1} \over 3}} \right) + {{f\left( x \right)} \over {{x^2} - 2x + 10}}} \right) + C∫(x2−2x+10)2dx​=A(tan−1(3x−1​)+x2−2x+10f(x)​)+C where C is a constant of integration then :
  1. A
    A =154{1 \over {54}}541​ and f(x) = 9(x–1)2
  2. B
    A =154{1 \over {54}}541​ and f(x) = 3(x–1)
  3. C
    A =181{1 \over {81}}811​ and f(x) = 3(x–1)
  4. D
    A =127{1 \over {27}}271​ and f(x) = 9(x–1)2
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