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Functions question

2004 · Shift 0 · Q70
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Functions question

2004 · Shift 0 · Q70

JEE MainMathematicsFunctionsMCQ+4 / −1
The domain of the function f(x)=sin⁡−1(x−3)9−x2f\left( x \right) = {{{{\sin }^{ - 1}}\left( {x - 3} \right)} \over {\sqrt {9 - {x^2}} }}f(x)=9−x2​sin−1(x−3)​
  1. A
    [1, 2]
  2. B
    [2, 3)
  3. C
    [1, 2)
  4. D
    [2, 3]
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