New chat PYQ Library Doubts Rank report

Sign in to see Recents

Sign in to save progress →

Functions question

2002 · Shift 0 · Q96

Guest · try one question or challengeGuest · try one question or challenge

PYQ Library
JEE Main
Mathematics
Functions
2002 · Shift 0 · Q96

Functions question

2002 · Shift 0 · Q96

JEE MainMathematicsFunctionsMCQ+4 / −1

Which one is not periodic?

A
$\left| {\sin 3x} \right| + {\sin ^2}x$
B
$\cos \sqrt x + {\cos ^2}x$
C
$\cos \,4x + {\tan ^2}x$
D
$cos\,2x + \sin x$

More from Functions

If the domain of the function $f (x) = \frac{1}{10 + 3 x - x ^{2}} + \frac{1}{x + ∣ x ∣}$ is $(1 + a)^{2} + b^{2}$ , then $(1 + a)^{2} + b^{2}$ is equal to :2025 · MCQ
$If the domain of the function f (x) = lo g_{e} (\frac{2 x - 3}{5 + 4 x}) + sin^{- 1} (\frac{4 + 3 x}{2 - x}) is [α, β), then α^{2} + 4 β is equal to$ 2025 · MCQ
Let $f$ be a function such that $f (x) + 3 f (\frac{24}{x}) = 4 x, x e q 0$ . Then $f (3) + f (8)$ is equal to2025 · MCQ
If the domain of the function $f (x) = lo g_{7} (1 - lo g_{4} (x^{2} - 9 x + 18))$ is $(α, β) \cup (γ, o)$ , then $α + β + γ + \overset{o}{^}$ is equal to2025 · MCQ
Let $f, g : (1, \infty) \to R$ be defined as $f (x) = \frac{2 x + 3}{5 x + 2}$ and $g (x) = \frac{2 - 3 x}{1 - x}$ . If the range of the function fog: $[2, 4] \to R$ is $\frac{1}{β - α}$ , then $\frac{1}{β - α}$ is…2025 · MCQ
Let the domains of the functions $f (x) = lo g_{4} lo g_{3} lo g_{7} (8 - lo g_{2} (x^{2} + 4 x + 5))$ and $g (x) = sin^{- 1} (\frac{7 x + 10}{x - 2})$ be $[γ, δ]$ and $α^{2} + β^{2} + γ^{2} + δ^{2}$ , respectively. Then $α^{2} + β^{2} + γ^{2} + δ^{2}$ …2025 · MCQ
If the range of the function $f (x) = \frac{5 - x}{x ^{2} - 3 x + 2}, x e q 1, 2,$ is $(- \infty, α] \cup [β, \infty)$ , then $α^{2} + β^{2}$ is equal to :2025 · MCQ
Let the domain of the function $f (x) = cos^{- 1} (\frac{4 x + 5}{3 x - 7})$ be $g (x) = lo g_{2} (2 - 6 lo g_{27} (2 x + 5))$ and the domain of $g (x) = lo g_{2} (2 - 6 lo g_{27} (2 x + 5))$ be $∣7 (α + β) + 4 (γ + δ) ∣$ . Then $∣7 (α + β) + 4 (γ + δ) ∣$ is…2025 · Numerical