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Differential Equations question

2024 · 8 Apr · Shift 2 · Q31
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  5. /2024 · 8 Apr · Shift 2 · Q31

Differential Equations question

2024 · 8 Apr · Shift 2 · Q31

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
Let y=y(x)y=y(x)y=y(x) be the solution curve of the differential equation sec⁡ydy dx+2xsin⁡y=x3cos⁡y,y(1)=0\sec y \frac{\mathrm{d} y}{\mathrm{~d} x}+2 x \sin y=x^3 \cos y, y(1)=0secy dxdy​+2xsiny=x3cosy,y(1)=0. Then y(3)y(\sqrt{3})y(3​) is equal to:
  1. A
    π6\frac{\pi}{6}6π​
  2. B
    π12\frac{\pi}{12}12π​
  3. C
    π3\frac{\pi}{3}3π​
  4. D
    π4\frac{\pi}{4}4π​
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