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Differential Equations question

2024 · 9 Apr · Shift 1 · Q35
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  5. /2024 · 9 Apr · Shift 1 · Q35

Differential Equations question

2024 · 9 Apr · Shift 1 · Q35

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
The solution of the differential equation (x2+y2)dx−5xy dy=0,y(1)=0(x^2+y^2) \mathrm{d} x-5 x y \mathrm{~d} y=0, y(1)=0(x2+y2)dx−5xy dy=0,y(1)=0, is :
  1. A
    ∣x2−4y2∣5=x2\left|x^2-4 y^2\right|^5=x^2​x2−4y2​5=x2
  2. B
    ∣x2−2y2∣6=x\left|x^2-2 y^2\right|^6=x​x2−2y2​6=x
  3. C
    ∣x2−2y2∣5=x2\left|x^2-2 y^2\right|^5=x^2​x2−2y2​5=x2
  4. D
    ∣x2−4y2∣6=x\left|x^2-4 y^2\right|^6=x​x2−4y2​6=x
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