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Differential Equations question

2022 · 28 Jun · Shift 2 · Q31
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  5. /2022 · 28 Jun · Shift 2 · Q31

Differential Equations question

2022 · 28 Jun · Shift 2 · Q31

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
Let x = x(y) be the solution of the differential equation 2y ex/y2dx+(y2−4xex/y2)dy=02y\,{e^{x/{y^2}}}dx + \left( {{y^2} - 4x{e^{x/{y^2}}}} \right)dy = 02yex/y2dx+(y2−4xex/y2)dy=0 such that x(1) = 0. Then, x(e) is equal to :
  1. A
    elog⁡e(2)e{\log _e}(2)eloge​(2)
  2. B
    −elog⁡e(2)- e{\log _e}(2)−eloge​(2)
  3. C
    e2log⁡e(2){e^2}{\log _e}(2)e2loge​(2)
  4. D
    −e2log⁡e(2)- {e^2}{\log _e}(2)−e2loge​(2)
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