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Differential Equations question

2022 · 26 Jun · Shift 2 · Q33
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  5. /2022 · 26 Jun · Shift 2 · Q33

Differential Equations question

2022 · 26 Jun · Shift 2 · Q33

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
If the solution of the differential equation dydx+ex(x2−2)y=(x2−2x)(x2−2)e2x{{dy} \over {dx}} + {e^x}\left( {{x^2} - 2} \right)y = \left( {{x^2} - 2x} \right)\left( {{x^2} - 2} \right){e^{2x}}dxdy​+ex(x2−2)y=(x2−2x)(x2−2)e2x satisfies y(0)=0y(0) = 0y(0)=0, then the value of y(2) is ‾\underline{\hspace{2cm}}​.
  1. A
    −-− 1
  2. B
    1
  3. C
    0
  4. D
    e
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