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Differential Equations question

2022 · 26 Jun · Shift 2 · Q32
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  5. /2022 · 26 Jun · Shift 2 · Q32

Differential Equations question

2022 · 26 Jun · Shift 2 · Q32

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
If y=y(x)y = y(x)y=y(x) is the solution of the differential equation xdydx+2y=x exx{{dy} \over {dx}} + 2y = x\,{e^x}xdxdy​+2y=xex, y(1)=0y(1) = 0y(1)=0 then the local maximum value of the function z(x)=x2y(x)−ex, x∈Rz(x) = {x^2}y(x) - {e^x},\,x \in Rz(x)=x2y(x)−ex,x∈R is :
  1. A
    1 −-− e
  2. B
    0
  3. C
    12{1 \over 2}21​
  4. D
    4e−e{4 \over e} - ee4​−e
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