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Differential Equations question

2022 · 28 Jul · Shift 1 · Q23

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JEE Main
Mathematics
Differential Equations
2022 · 28 Jul · Shift 1 · Q23

Differential Equations question

2022 · 28 Jul · Shift 1 · Q23

JEE MainMathematicsDifferential EquationsMCQ+4 / −1

Let the solution curve of the differential equation

x \mathrm{~d} y=\left(\sqrt{x^{2}+y^{2}}+y\right) \mathrm{d} x, x\gt 0

, intersect the line

x=1

at

y=0

and the line

x=2

at

y=\alpha

. Then the value of

\alpha

is :

A
$\frac{1}{2}$
B
$\frac{3}{2}$
C
$-\frac{3}{2}$
D
$\frac{5}{2}$

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