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Differential Equations question

2022 · 27 Jun · Shift 2 · Q43
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  5. /2022 · 27 Jun · Shift 2 · Q43

Differential Equations question

2022 · 27 Jun · Shift 2 · Q43

JEE MainMathematicsDifferential EquationsNumerical+4 / −1
Let y=y(x)y = y(x)y=y(x) be the solution of the differential equation (1−x2)dy=(xy+(x3+2)1−x2)dx,−1(1 - {x^2})dy = \left( {xy + ({x^3} + 2)\sqrt {1 - {x^2}} } \right)dx, - 1(1−x2)dy=(xy+(x3+2)1−x2​)dx,−1-$$1 is equal to $\underline{\hspace{2cm}}$.
Numerical answer
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