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Differential Equations question

2022 · 26 Jun · Shift 1 · Q36
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  5. /2022 · 26 Jun · Shift 1 · Q36

Differential Equations question

2022 · 26 Jun · Shift 1 · Q36

JEE MainMathematicsDifferential EquationsNumerical+4 / −1
Let the solution curve y = y(x) of the differential equation (4+x2)dy−2x(x2+3y+4)dx=0(4 + {x^2})dy - 2x({x^2} + 3y + 4)dx = 0(4+x2)dy−2x(x2+3y+4)dx=0 pass through the origin. Then y(2) is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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