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Differential Equations question

2022 · 25 Jun · Shift 2 · Q32

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JEE Main
Mathematics
Differential Equations
2022 · 25 Jun · Shift 2 · Q32

Differential Equations question

2022 · 25 Jun · Shift 2 · Q32

JEE MainMathematicsDifferential EquationsMCQ+4 / −1

If

y = y(x)

is the solution of the differential equation

2{x^2}{{dy} \over {dx}} - 2xy + 3{y^2} = 0

such that

y(e) = {e \over 3}

, then y(1) is equal to :

A
${1 \over 3}$
B
${2 \over 3}$
C
${3 \over 2}$
D
3

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