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Differential Equations question

2021 · 31 Aug · Shift 2 · Q29
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  5. /2021 · 31 Aug · Shift 2 · Q29

Differential Equations question

2021 · 31 Aug · Shift 2 · Q29

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
If ydydx=x[y2x2+ϕ(y2x2)ϕ′(y2x2)]y{{dy} \over {dx}} = x\left[ {{{{y^2}} \over {{x^2}}} + {{\phi \left( {{{{y^2}} \over {{x^2}}}} \right)} \over {\phi '\left( {{{{y^2}} \over {{x^2}}}} \right)}}} \right]ydxdy​=x​x2y2​+ϕ′(x2y2​)ϕ(x2y2​)​​, x > 0, ϕ\phiϕ> 0, and y(1) =−-− 1, then ϕ(y24)\phi \left( {{{{y^2}} \over 4}} \right)ϕ(4y2​) is equal to :
  1. A
    4 ϕ\phiϕ (2)
  2. B
    4 ϕ\phiϕ (1)
  3. C
    2 ϕ\phiϕ (1)
  4. D
    ϕ\phiϕ (1)
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