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Differential Equations question

2020 · 5 Sep · Shift 1 · Q39
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  5. /2020 · 5 Sep · Shift 1 · Q39

Differential Equations question

2020 · 5 Sep · Shift 1 · Q39

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
If y = y(x) is the solution of the differential equation 5+ex2+y.dydx+ex=0{{5 + {e^x}} \over {2 + y}}.{{dy} \over {dx}} + {e^x} = 02+y5+ex​.dxdy​+ex=0 satisfying y(0) = 1, then a value of y(loge13) is :
  1. A
    -1
  2. B
    1
  3. C
    0
  4. D
    2
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