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Differential Equations question

2020 · 4 Sep · Shift 1 · Q38

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JEE Main
Mathematics
Differential Equations
2020 · 4 Sep · Shift 1 · Q38

Differential Equations question

2020 · 4 Sep · Shift 1 · Q38

JEE MainMathematicsDifferential EquationsMCQ+4 / −1

Let y = y(x) be the solution of the differential equation, xy'- y = x2(xcosx + sinx), x > 0. if y (

\pi

) =

\pi

then

y''\left( {{\pi \over 2}} \right) + y\left( {{\pi \over 2}} \right)

is equal to :

A
$1 + {\pi \over 2}$
B
$2 + {\pi \over 2} + {{{\pi ^2}} \over 4}$
C
$2 + {\pi \over 2}$
D
$1 + {\pi \over 2} + {{{\pi ^2}} \over 4}$

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