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Differential Equations question

2020 · 5 Sep · Shift 2 · Q20

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JEE Main
Mathematics
Differential Equations
2020 · 5 Sep · Shift 2 · Q20

Differential Equations question

2020 · 5 Sep · Shift 2 · Q20

JEE MainMathematicsDifferential EquationsMCQ+4 / −1

Let y = y(x) be the solution of the differential equation cosx

{{dy} \over {dx}}

+ 2ysinx = sin2x, x

\in

\left( {0,{\pi \over 2}} \right)

. If y

\left( {{\pi \over 3}} \right)

= 0, then y

\left( {{\pi \over 4}} \right)

is equal to :

A
${1 \over {\sqrt 2 }} - 1$
B
${\sqrt 2 - 2}$
C
${2 - \sqrt 2 }$
D
${2 + \sqrt 2 }$

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