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Differential Equations question

2020 · 2 Sep · Shift 1 · Q37

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JEE Main
Mathematics
Differential Equations
2020 · 2 Sep · Shift 1 · Q37

Differential Equations question

2020 · 2 Sep · Shift 1 · Q37

JEE MainMathematicsDifferential EquationsMCQ+4 / −1

Let y = y(x) be the solution of the differential equation,

{{2 + \sin x} \over {y + 1}}.{{dy} \over {dx}} = - \cos x

, y > 0,y(0) = 1. If y(

\pi

) = a and

{{dy} \over {dx}}

at x =

\pi

is b, then the ordered pair (a, b) is equal to :

A
(2, 1)
B
$\left( {2,{3 \over 2}} \right)$
C
(1, -1)
D
(1, 1)

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