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Differential Equations question

2021 · 18 Mar · Shift 2 · Q23
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  2. /JEE Main
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  4. /Differential Equations
  5. /2021 · 18 Mar · Shift 2 · Q23

Differential Equations question

2021 · 18 Mar · Shift 2 · Q23

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
Let y = y(x) be the solution of the differential equation dydx=(y+1)((y+1)ex2/2−x){{dy} \over {dx}} = (y + 1)\left( {(y + 1){e^{{x^2}/2}} - x} \right)dxdy​=(y+1)((y+1)ex2/2−x), 0 < x < 2.1, with y(2) = 0. Then the value of dydx{{dy} \over {dx}}dxdy​ at x = 1 is equal to :
  1. A
    e5/2(1+e2)2{{{e^{5/2}}} \over {{{(1 + {e^2})}^2}}}(1+e2)2e5/2​
  2. B
    5e1/2(e2+1)2{{5{e^{1/2}}} \over {{{({e^2} + 1)}^2}}}(e2+1)25e1/2​
  3. C
    −2e2(1+e2)2- {{2{e^2}} \over {{{(1 + {e^2})}^2}}}−(1+e2)22e2​
  4. D
    −e3/2(e2+1)2{{ - {e^{3/2}}} \over {{{({e^2} + 1)}^2}}}(e2+1)2−e3/2​
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