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Differential Equations question

2020 · 9 Jan · Shift 2 · Q27

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JEE Main
Mathematics
Differential Equations
2020 · 9 Jan · Shift 2 · Q27

Differential Equations question

2020 · 9 Jan · Shift 2 · Q27

JEE MainMathematicsDifferential EquationsMCQ+4 / −1

If

{{dy} \over {dx}} = {{xy} \over {{x^2} + {y^2}}}

; y(1) = 1; then a value of x satisfying y(x) = e is :

A
$\sqrt 2 e$
B
${1 \over 2}\sqrt 3 e$
C
${e \over {\sqrt 2 }}$
D
$\sqrt 3 e$

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