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Differential Equations question

2020 · 7 Jan · Shift 2 · Q37

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JEE Main
Mathematics
Differential Equations
2020 · 7 Jan · Shift 2 · Q37

Differential Equations question

2020 · 7 Jan · Shift 2 · Q37

JEE MainMathematicsDifferential EquationsMCQ+4 / −1

Let y = y(x) be the solution curve of the differential equation,

\left( {{y^2} - x} \right){{dy} \over {dx}} = 1

, satisfying y(0) = 1. This curve intersects the x-axis at a point whose abscissa is :

A
2 + e
B
-e
C
2
D
2 - e

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