New chat PYQ Library Doubts Rank report

Sign in to see Recents

Sign in to save progress →

Differential Equations question

2020 · 7 Jan · Shift 1 · Q35

Guest · try one question or challengeGuest · try one question or challenge

PYQ Library
JEE Main
Mathematics
Differential Equations
2020 · 7 Jan · Shift 1 · Q35

Differential Equations question

2020 · 7 Jan · Shift 1 · Q35

JEE MainMathematicsDifferential EquationsMCQ+4 / −1

If y = y(x) is the solution of the differential equation,

{e^y}\left( {{{dy} \over {dx}} - 1} \right) = {e^x}

such that y(0) = 0, then y(1) is equal to:

A
2 + loge2
B
loge2
C
1 + loge2
D
2e

More from Differential Equations

Let y = y(x) be the solution curve of the differential equation, $(y^{2} - x) \frac{d y}{d x} = 1$ , satisfying y(0) = 1. This curve intersects the x-axis at a point whose abscissa is :2020 · MCQ
Let y = y(x) be a solution of the differential equation, $1 - x^{2} \frac{d y}{d x} + 1 - y^{2} = 0$ , |x| < 1. If $y (\frac{1}{2}) = \frac{3}{2}$ , then $y (- \frac{1}{2})$ …2020 · MCQ
If for x $\geq$ 0, y = y(x) is the solution of the differential equation (x + 1)dy = ((x + 1)2 + y – 3)dx, y(2) = 0, then y(3) is equal to .2020 · Numerical
If $\frac{d y}{d x} = \frac{x y}{x ^{2} + y ^{2}}$ ; y(1) = 1; then a value of x satisfying y(x) = e is :2020 · MCQ
Let y = y(x) be the solution of the differential equation, $(x^{2} + 1)^{2} \frac{d y}{d x} + 2 x (x^{2} + 1) y = 1$ such that y(0) = 0. If $a y (1)$ = $\frac{π}{32}$ , then the value of 'a' is :2019 · MCQ
The solution of the differential equation $x \frac{d y}{d x} + 2 y$ = x2 (x $e$ 0) with y(1) = 1, is :2019 · MCQ
If $cos x \frac{d y}{d x} - y sin x = 6 x$ , (0 < x < $\frac{π}{2}$ ) and $y (\frac{π}{3})$ = 0 then $y (\frac{π}{6})$ is equal to :-2019 · MCQ
If y = y(x) is the solution of the differential equation, x $\frac{d y}{d x}$ + 2y = x2, satisfying y(1) = 1, then y( $\frac{1}{2}$ ) is equal to :2019 · MCQ