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Complex Numbers question

2025 · 24 Jan · Shift 1 · Q32
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  5. /2025 · 24 Jan · Shift 1 · Q32

Complex Numbers question

2025 · 24 Jan · Shift 1 · Q32

JEE MainMathematicsComplex NumbersMCQ+4 / −1
If α\alphaα and β\betaβ are the roots of the equation 2z2−3z−2i=02 z^2-3 z-2 i=02z2−3z−2i=0, where i=−1i=\sqrt{-1}i=−1​, then 16⋅Re⁡(α19+β19+α11+β11α15+β15)⋅lm⁡(α19+β19+α11+β11α15+β15)16 \cdot \operatorname{Re}\left(\frac{\alpha^{19}+\beta^{19}+\alpha^{11}+\beta^{11}}{\alpha^{15}+\beta^{15}}\right) \cdot \operatorname{lm}\left(\frac{\alpha^{19}+\beta^{19}+\alpha^{11}+\beta^{11}}{\alpha^{15}+\beta^{15}}\right)16⋅Re(α15+β15α19+β19+α11+β11​)⋅lm(α15+β15α19+β19+α11+β11​) is equal to
  1. A
    441
  2. B
    312
  3. C
    409
  4. D
    398
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