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Complex Numbers question

2025 · 8 Apr · Shift 2 · Q35
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  5. /2025 · 8 Apr · Shift 2 · Q35

Complex Numbers question

2025 · 8 Apr · Shift 2 · Q35

JEE MainMathematicsComplex NumbersMCQ+4 / −1
Let A={θ∈[0,2π]:1+10Re⁡(2cos⁡θ+isin⁡θcos⁡θ−3isin⁡θ)=0}A = \left\{ \theta \in [0, 2\pi] : 1 + 10\operatorname{Re}\left( \frac{2\cos\theta + i\sin\theta}{\cos\theta - 3i\sin\theta} \right) = 0 \right\}A={θ∈[0,2π]:1+10Re(cosθ−3isinθ2cosθ+isinθ​)=0}. Then ∑θ∈Aθ2\sum\limits_{\theta \in A} \theta^2θ∈A∑​θ2 is equal to
  1. A
    214π2\frac{21}{4} \pi^2421​π2
  2. B
    6π26\pi^26π2
  3. C
    274π2\frac{27}{4} \pi^2427​π2
  4. D
    8π28\pi^28π2
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