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Complex Numbers question

2025 · 7 Apr · Shift 2 · Q28
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  5. /2025 · 7 Apr · Shift 2 · Q28

Complex Numbers question

2025 · 7 Apr · Shift 2 · Q28

JEE MainMathematicsComplex NumbersMCQ+4 / −1
If the locus of z ∈ ℂ, such that Re (z−12z+i)+Re(z‾−12z‾−i)=2\left( \frac{z - 1}{2z + i} \right) + \text{Re} \left( \frac{\overline{z} - 1}{2\overline{z} - i} \right) = 2(2z+iz−1​)+Re(2z−iz−1​)=2, is a circle of radius r and center (a,b)(a, b)(a,b), then 15abr2\frac{15ab}{r^2}r215ab​ is equal to :
  1. A
    16
  2. B
    24
  3. C
    12
  4. D
    18
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