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Binomial Theorem question

2024 · 29 Jan · Shift 1 · Q55
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  5. /2024 · 29 Jan · Shift 1 · Q55

Binomial Theorem question

2024 · 29 Jan · Shift 1 · Q55

JEE MainMathematicsBinomial TheoremNumerical+4 / −1
 If 11C12+11C23+…+11C910=nm with gcd⁡(n,m)=1, then n+m is equal to \text { If } \frac{{ }^{11} C_1}{2}+\frac{{ }^{11} C_2}{3}+\ldots+\frac{{ }^{11} C_9}{10}=\frac{n}{m} \text { with } \operatorname{gcd}(n, m)=1 \text {, then } n+m \text { is equal to } If 211C1​​+311C2​​+…+1011C9​​=mn​ with gcd(n,m)=1, then n+m is equal to  ‾\underline{\hspace{2cm}}​.
Numerical answer
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