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Binomial Theorem question

2024 · 31 Jan · Shift 1 · Q47
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  5. /2024 · 31 Jan · Shift 1 · Q47

Binomial Theorem question

2024 · 31 Jan · Shift 1 · Q47

JEE MainMathematicsBinomial TheoremMCQ+4 / −1
Let aaa be the sum of all coefficients in the expansion of (1−2x+2x2)2023(3−4x2+2x3)2024\left(1-2 x+2 x^2\right)^{2023}\left(3-4 x^2+2 x^3\right)^{2024}(1−2x+2x2)2023(3−4x2+2x3)2024 and b=lim⁡x→0(∫0xlog⁡(1+t)t2024+1dtx2)b=\lim_{x \rightarrow 0}\left(\frac{\int_0^x \frac{\log (1+t)}{t^{2024}+1} d t}{x^2}\right)b=x→0lim​(x2∫0x​t2024+1log(1+t)​dt​). If the equation cx2+dx+e=0c x^2+d x+e=0cx2+dx+e=0 and 2bx2+ax+4=02 b x^2+a x+4=02bx2+ax+4=0 have a common root, where c,d,e∈Rc, d, e \in \mathbb{R}c,d,e∈R, then d:c:\mathrm{d}: \mathrm{c}:d:c: e equals
  1. A
    2:1:42: 1: 42:1:4
  2. B
    1:1:41: 1: 41:1:4
  3. C
    1:2:41: 2: 41:2:4
  4. D
    4:1:44: 1: 44:1:4
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