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Binomial Theorem question

2024 · 30 Jan · Shift 2 · Q59
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  5. /2024 · 30 Jan · Shift 2 · Q59

Binomial Theorem question

2024 · 30 Jan · Shift 2 · Q59

JEE MainMathematicsBinomial TheoremNumerical+4 / −1
Let α=∑k=0n((nCk)2k+1)\alpha=\sum_{k=0}^n\left(\frac{\left({ }^n C_k\right)^2}{k+1}\right)α=k=0∑n​(k+1(nCk​)2​) and β=∑k=0n−1(nCknCk+1k+2)\beta=\sum_{k=0}^{n-1}\left(\frac{{ }^n C_k{ }^n C_{k+1}}{k+2}\right)β=k=0∑n−1​(k+2nCk​nCk+1​​) If 5α=6β5 \alpha=6 \beta5α=6β, then nnn equals ‾\underline{\hspace{2cm}}​.
Numerical answer
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