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Binomial Theorem question

2024 · 31 Jan · Shift 1 · Q52
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  5. /2024 · 31 Jan · Shift 1 · Q52

Binomial Theorem question

2024 · 31 Jan · Shift 1 · Q52

JEE MainMathematicsBinomial TheoremNumerical+4 / −1
In the expansion of (1+x)(1−x2)(1+3x+3x2+1x3)5,xeq0(1+x)\left(1-x^2\right)\left(1+\frac{3}{x}+\frac{3}{x^2}+\frac{1}{x^3}\right)^5, x eq 0(1+x)(1−x2)(1+x3​+x23​+x31​)5,xeq0, the sum of the coefficients of x3x^3x3 and x−13x^{-13}x−13 is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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