Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents

Your guest activity stays on this device

Sign in to save progress →
Sign in

Application of Derivatives question

2025 · 28 Jan · Shift 1 · Q40
Guest · filters and generic practice availableBrowsing as a guest · PYQ filters and generic practice are available. Sign in only for personalised features and saved progress.
  1. PYQ Library
  2. /JEE Main
  3. /Mathematics
  4. /Application of Derivatives
  5. /2025 · 28 Jan · Shift 1 · Q40

Application of Derivatives question

2025 · 28 Jan · Shift 1 · Q40

JEE MainMathematicsApplication of DerivativesMCQ+4 / −1
The sum of all local minimum values of the function f(x)={1−2x,x2\mathrm{f}(x)=\left\{\begin{array}{lr} 1-2 x, & x2 \end{array}\right.f(x)={1−2x,​x2​ is
  1. A
    16772\frac{167}{72}72167​
  2. B
    15772\frac{157}{72}72157​
  3. C
    17172\frac{171}{72}72171​
  4. D
    13172\frac{131}{72}72131​
View written solutionFree

Correct answer: B

The function in the prompt is visibly truncated in the rendering:

f(x)={1−2x,x2f(x)=\left\{\begin{array}{lr}1-2x, & x2\end{array}\right.f(x)={1−2x,​x2​

So the piecewise definition is incomplete, and the second branch is missing. As written, the function is not fully specified, so the local minima cannot be determined uniquely from the visible text alone.

1. What can be read from the question

The first visible branch is f(x)=1−2xf(x)=1-2xf(x)=1−2x for some condition involving xxx (likely x<2x<2x<2 or x≤2x\le 2x≤2, but the symbol is cut off).

However, the rest of the piecewise function is absent. Since local minimum values depend crucially on the other branch and on the joining behavior near the boundary point, we cannot derive the minima from the displayed expression alone.

2. Why the answer cannot be rigorously determined

For a piecewise function, local minima may occur:

  1. inside each interval, by solving f′(x)=0f'(x)=0f′(x)=0,
  2. at the junction point(s), by checking one-sided behavior.

Because the second branch is missing, both the derivative analysis and the junction analysis are impossible to complete.

3. Comparison with stored answer

The stored correct answer is B, i.e. 15772.\frac{157}{72}.72157​.

But with the function definition incomplete, I cannot verify this mathematically from the provided statement.

So I must disagree with the stored answer based on the available text, not because 15772\frac{157}{72}72157​ is necessarily wrong, but because the question as shown is incomplete and insufficient to solve.

If you provide the full piecewise function, I can solve it completely and verify the correct option exactly.

PreviousNext

More from Application of Derivatives

  • If 5f(x)+4f(x1​)=x2−2,∀xeq0 and y=9x2f(x), then y is strictly increasing in :2024 · MCQ
  • Let the sum of the maximum and the minimum values of the function f(x)=2x2+3x+82x2−3x+8​ be nm​, where gcd(m,n)=1. Then m+n is equal to :2024 · MCQ
  • Let f(x)=3x−2​+4−x​ be a real valued function. If α and β are respectively the minimum and the maximum values of f, then α2+2β2 is equal to2024 · MCQ
  • Let a rectangle ABCD of sides 2 and 4 be inscribed in another rectangle PQRS such that the vertices of the rectangle ABCD lie on the sides of the rectangle PQRS. Let a and b be the sides of the rectangle PQRS when its area is maximum. Then…2024 · MCQ
  • Let f(x)=x5+2x3+3x+1,x∈R, and g(x) be a function such that g(f(x))=x for all x∈R. Then g′(7)g(7)​ is equal to :2024 · MCQ
  • For the function f(x)=sinx+3x−π2​(x2+x), where x∈[0,2π​], consider the following two statements : (I) f is increasing in (0,2π​). (II) f′…2024 · MCQ
  • Let the maximum and minimum values of (8x−x2−12​−4)2+(x−7)2,x∈R be M and m, respectively. Then M2−m2 is equal to ​.2024 · Numerical
  • The interval in which the function f(x)=xx,x>0, is strictly increasing is2024 · MCQ