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Application of Derivatives question

2024 · 4 Apr · Shift 1 · Q47
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  5. /2024 · 4 Apr · Shift 1 · Q47

Application of Derivatives question

2024 · 4 Apr · Shift 1 · Q47

JEE MainMathematicsApplication of DerivativesMCQ+4 / −1
Let the sum of the maximum and the minimum values of the function f(x)=2x2−3x+82x2+3x+8f(x)=\frac{2 x^2-3 x+8}{2 x^2+3 x+8}f(x)=2x2+3x+82x2−3x+8​ be mn\frac{m}{n}nm​, where gcd⁡(m,n)=1\operatorname{gcd}(\mathrm{m}, \mathrm{n})=1gcd(m,n)=1. Then m+n\mathrm{m}+\mathrm{n}m+n is equal to :
  1. A
    217
  2. B
    182
  3. C
    201
  4. D
    195
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