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Application of Derivatives question

2024 · 5 Apr · Shift 2 · Q53
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  5. /2024 · 5 Apr · Shift 2 · Q53

Application of Derivatives question

2024 · 5 Apr · Shift 2 · Q53

JEE MainMathematicsApplication of DerivativesNumerical+4 / −1
Let the maximum and minimum values of (8x−x2−12−4)2+(x−7)2,x∈R\left(\sqrt{8 x-x^2-12}-4\right)^2+(x-7)^2, x \in \mathbf{R}(8x−x2−12​−4)2+(x−7)2,x∈R be M\mathrm{M}M and m\mathrm{m}m, respectively. Then M2−m2\mathrm{M}^2-\mathrm{m}^2M2−m2 is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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