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3D Geometry question

2025 · 23 Jan · Shift 2 · Q36

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JEE Main
Mathematics
3D Geometry
2025 · 23 Jan · Shift 2 · Q36

3D Geometry question

2025 · 23 Jan · Shift 2 · Q36

JEE MainMathematics3D GeometryMCQ+4 / −1

The distance of the line

\frac{x-2}{2}=\frac{y-6}{3}=\frac{z-3}{4}

from the point

(1,4,0)

along the line

\frac{x}{1}=\frac{y-2}{2}=\frac{z+3}{3}

is :

A
$\sqrt{17}$
B
$\sqrt{13}$
C
$\sqrt{15}$
D
$\sqrt{14}$

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