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3D Geometry question

2024 · 27 Jan · Shift 1 · Q43
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  5. /2024 · 27 Jan · Shift 1 · Q43

3D Geometry question

2024 · 27 Jan · Shift 1 · Q43

JEE MainMathematics3D GeometryMCQ+4 / −1
If the shortest distance between the lines x−41=y+12=z−3\frac{x-4}{1}=\frac{y+1}{2}=\frac{z}{-3}1x−4​=2y+1​=−3z​ and x−λ2=y+14=z−2−5\frac{x-\lambda}{2}=\frac{y+1}{4}=\frac{z-2}{-5}2x−λ​=4y+1​=−5z−2​ is 65\frac{6}{\sqrt{5}}5​6​, then the sum of all possible values of λ\lambdaλ is :
  1. A
    10
  2. B
    5
  3. C
    7
  4. D
    8
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