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3D Geometry question

2024 · 27 Jan · Shift 1 · Q37
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  5. /2024 · 27 Jan · Shift 1 · Q37

3D Geometry question

2024 · 27 Jan · Shift 1 · Q37

JEE MainMathematics3D GeometryMCQ+4 / −1
The distance, of the point (7,−2,11)(7,-2,11)(7,−2,11) from the line x−61=y−40=z−83\frac{x-6}{1}=\frac{y-4}{0}=\frac{z-8}{3}1x−6​=0y−4​=3z−8​ along the line x−52=y−1−3=z−56\frac{x-5}{2}=\frac{y-1}{-3}=\frac{z-5}{6}2x−5​=−3y−1​=6z−5​, is :
  1. A
    12
  2. B
    18
  3. C
    21
  4. D
    14
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