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3D Geometry question

2024 · 27 Jan · Shift 2 · Q53
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  5. /2024 · 27 Jan · Shift 2 · Q53

3D Geometry question

2024 · 27 Jan · Shift 2 · Q53

JEE MainMathematics3D GeometryNumerical+4 / −1
The lines x−22=y−2=z−716\frac{x-2}{2}=\frac{y}{-2}=\frac{z-7}{16}2x−2​=−2y​=16z−7​ and x+34=y+23=z+21\frac{x+3}{4}=\frac{y+2}{3}=\frac{z+2}{1}4x+3​=3y+2​=1z+2​ intersect at the point PPP. If the distance of P\mathrm{P}P from the line x+12=y−13=z−11\frac{x+1}{2}=\frac{y-1}{3}=\frac{z-1}{1}2x+1​=3y−1​=1z−1​ is lll, then 14l214 l^214l2 is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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