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3D Geometry question

2024 · 30 Jan · Shift 1 · Q37
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  5. /2024 · 30 Jan · Shift 1 · Q37

3D Geometry question

2024 · 30 Jan · Shift 1 · Q37

JEE MainMathematics3D GeometryMCQ+4 / −1
Let (α,β,γ)(\alpha, \beta, \gamma)(α,β,γ) be the foot of perpendicular from the point (1,2,3)(1,2,3)(1,2,3) on the line x+35=y−12=z+43\frac{x+3}{5}=\frac{y-1}{2}=\frac{z+4}{3}5x+3​=2y−1​=3z+4​. Then 19(α+β+γ)19(\alpha+\beta+\gamma)19(α+β+γ) is equal to :
  1. A
    99
  2. B
    102
  3. C
    101
  4. D
    100
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