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3D Geometry question

2024 · 29 Jan · Shift 2 · Q51
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3D Geometry question

2024 · 29 Jan · Shift 2 · Q51

JEE MainMathematics3D GeometryNumerical+4 / −1
Let O be the origin, and M and N\mathrm{N}N be the points on the lines x−54=y−41=z−53\frac{x-5}{4}=\frac{y-4}{1}=\frac{z-5}{3}4x−5​=1y−4​=3z−5​ and x+812=y+25=z+119\frac{x+8}{12}=\frac{y+2}{5}=\frac{z+11}{9}12x+8​=5y+2​=9z+11​ respectively such that MN\mathrm{MN}MN is the shortest distance between the given lines. Then OM→⋅ON→\overrightarrow{O M} \cdot \overrightarrow{O N}OM⋅ON is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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