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3D Geometry question

2024 · 9 Apr · Shift 2 · Q56
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3D Geometry question

2024 · 9 Apr · Shift 2 · Q56

JEE MainMathematics3D GeometryNumerical+4 / −1
The square of the distance of the image of the point (6,1,5)(6,1,5)(6,1,5) in the line x−13=y2=z−24\frac{x-1}{3}=\frac{y}{2}=\frac{z-2}{4}3x−1​=2y​=4z−2​, from the origin is ‾\underline{\hspace{2cm}}​.
Numerical answer
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