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3D Geometry question

2024 · 9 Apr · Shift 1 · Q44

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JEE Main
Mathematics
3D Geometry
2024 · 9 Apr · Shift 1 · Q44

3D Geometry question

2024 · 9 Apr · Shift 1 · Q44

JEE MainMathematics3D GeometryMCQ+4 / −1

The shortest distance between the lines

\frac{x-3}{4}=\frac{y+7}{-11}=\frac{z-1}{5}

and

\frac{x-5}{3}=\frac{y-9}{-6}=\frac{z+2}{1}

is:

A
$\frac{185}{\sqrt{563}}$
B
$\frac{187}{\sqrt{563}}$
C
$\frac{178}{\sqrt{563}}$
D
$\frac{179}{\sqrt{563}}$

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