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3D Geometry question

2024 · 8 Apr · Shift 2 · Q32

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JEE Main
Mathematics
3D Geometry
2024 · 8 Apr · Shift 2 · Q32

3D Geometry question

2024 · 8 Apr · Shift 2 · Q32

JEE MainMathematics3D GeometryMCQ+4 / −1

If the shortest distance between the lines

\frac{x-\lambda}{2}=\frac{y-4}{3}=\frac{z-3}{4}

and

\frac{x-2}{4}=\frac{y-4}{6}=\frac{z-7}{8}

is

\frac{13}{\sqrt{29}}

, then a value of

\lambda

is :

A
$\frac{13}{25}$
B
1
C
$-$ 1
D
$-\frac{13}{25}$

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