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3D Geometry question

2016 · 9 Apr · Shift 1 · Q36
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  5. /2016 · 9 Apr · Shift 1 · Q36

3D Geometry question

2016 · 9 Apr · Shift 1 · Q36

JEE MainMathematics3D GeometryMCQ+4 / −1
The shortest distance between the lines x2=y2=z1{x \over 2} = {y \over 2} = {z \over 1}2x​=2y​=1z​ and x+2−1=y−48=z−54{{x + 2} \over { - 1}} = {{y - 4} \over 8} = {{z - 5} \over 4}−1x+2​=8y−4​=4z−5​ lies in the interval :
  1. A
    [0, 1)
  2. B
    [1, 2)
  3. C
    (2, 3]
  4. D
    (3, 4]
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