JEE MainChemistryThermodynamicsMCQ+4 / −1
If (diamond (graphite) C (diamond) C (graphite) at constant temperature. Then
- A−X = Y + Z
- BX = Y − Z
- CX = −Y + Z
- DX = Y + Z
View written solutionFree
Correct answer: B
-
Interpret the given thermochemical equations
The reactions are written as heat being evolved:
Since heat appears on the product side, the enthalpy changes are:
-
Apply Hess's law
To go from diamond to , we can follow two paths:
-
Direct path: with enthalpy change .
-
Indirect path: first convert diamond to graphite, then burn graphite:
Total enthalpy change:
By Hess's law, both paths must have the same enthalpy change:
-
-
Rearrange
Hence,
-
Check options
- A: ❌
- B: ✅
- C: ❌
- D: ❌
Therefore, the correct option is B.
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