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Thermodynamics question

2024 · 29 Jan · Shift 2 · Q22
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Thermodynamics question

2024 · 29 Jan · Shift 2 · Q22

JEE MainChemistryThermodynamicsNumerical+4 / −1
Standard enthalpy of vapourisation for CCl4\mathrm{CCl}_4CCl4​ is 30.5 kJ mol−130.5 \mathrm{~kJ} \mathrm{~mol}^{-1}30.5 kJ mol−1. Heat required for vapourisation of 284 g284 \mathrm{~g}284 g of CCl4\mathrm{CCl}_4CCl4​ at constant temperature is ‾\underline{\hspace{2cm}}​kJ\mathrm{kJ}kJ. (Given molar mass in gmol−1;C=12,Cl=35.5\mathrm{g} \mathrm{mol}^{-1} ; \mathrm{C}=12, \mathrm{Cl}=35.5gmol−1;C=12,Cl=35.5)
Numerical answer
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