1. Work done in a cyclic process

   For a cyclic transformation on a $P$–$V$ diagram, the net work done is equal to the area enclosed by the cycle.

2. Shape of the path $A \to B \to C \to A$

   From the diagram, the cycle forms a triangle in the $P$–$V$ plane.

   Hence, $W = \text{Area of triangle} = \frac{1}{2} \times (\Delta V) \times (\Delta P)$

3. Reading values from the graph

   From the given figure:

   • Change in volume, $\Delta V = 2\,\text{m}^3$
   • Change in pressure, $\Delta P = 200\,\text{Pa}$

4. Calculate the enclosed area

   $W = \frac{1}{2} \times 2 \times 200 = 200\,\text{J}$

5. Direction of the cycle

   Since the path $A \to B \to C \to A$ is clockwise, the work done by the gas is positive.

Therefore, the total work done in the cyclic process is $\boxed{200\,\text{J}}$