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Thermodynamics question

2024 · 30 Jan · Shift 2 · Q30
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  5. /2024 · 30 Jan · Shift 2 · Q30

Thermodynamics question

2024 · 30 Jan · Shift 2 · Q30

JEE MainChemistryThermodynamicsNumerical+4 / −1
Two reactions are given below: 2Fe(s)+32O2( g)→Fe2O3( s),ΔH∘=−822 kJ/molC(s)+12O2( g)→CO(g),ΔH∘=−110 kJ/mol\begin{aligned} & 2 \mathrm{Fe}_{(\mathrm{s})}+\frac{3}{2} \mathrm{O}_{2(\mathrm{~g})} \rightarrow \mathrm{Fe}_2 \mathrm{O}_{3(\mathrm{~s})}, \Delta \mathrm{H}^{\circ}=-822 \mathrm{~kJ} / \mathrm{mol} \\ & \mathrm{C}_{(\mathrm{s})}+\frac{1}{2} \mathrm{O}_{2(\mathrm{~g})} \rightarrow \mathrm{CO}_{(\mathrm{g})}, \Delta \mathrm{H}^{\circ}=-110 \mathrm{~kJ} / \mathrm{mol} \end{aligned}​2Fe(s)​+23​O2( g)​→Fe2​O3( s)​,ΔH∘=−822 kJ/molC(s)​+21​O2( g)​→CO(g)​,ΔH∘=−110 kJ/mol​ Then enthalpy change for following reaction 3C(s)+Fe2O3( s)→2Fe(s)+3CO(g)3 \mathrm{C}_{(\mathrm{s})}+\mathrm{Fe}_2 \mathrm{O}_{3(\mathrm{~s})} \rightarrow 2 \mathrm{Fe}_{(\mathrm{s})}+3 \mathrm{CO}_{(\mathrm{g})}3C(s)​+Fe2​O3( s)​→2Fe(s)​+3CO(g)​ is ‾\underline{\hspace{2cm}}​kJ/mol\mathrm{kJ} / \mathrm{mol}kJ/mol.
Numerical answer
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