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Thermodynamics question

2024 · 27 Jan · Shift 2 · Q30
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Thermodynamics question

2024 · 27 Jan · Shift 2 · Q30

JEE MainChemistryThermodynamicsNumerical+4 / −1
For a certain thermochemical reaction M→N\mathrm{M} \rightarrow \mathrm{N}M→N at T=400 K,ΔH⊖=77.2 kJ mol−1,ΔS=122 JK−1,log⁡\mathrm{T}=400 \mathrm{~K}, \Delta \mathrm{H}^{\ominus}=77.2 \mathrm{~kJ} \mathrm{~mol}^{-1}, \Delta \mathrm{S}=122 \mathrm{~JK}^{-1}, \logT=400 K,ΔH⊖=77.2 kJ mol−1,ΔS=122 JK−1,log equilibrium constant (log⁡K)(\log K)(logK) is ‾\underline{\hspace{2cm}}​×10−1\times 10^{-1}×10−1.
Numerical answer
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