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Thermodynamics question

2021 · 25 Feb · Shift 1 · Q17
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Thermodynamics question

2021 · 25 Feb · Shift 1 · Q17

JEE MainChemistryThermodynamicsNumerical+4 / −1
The ionization enthalpy of Na+Na^+Na+ formation from NaNaNa(g) is 495.8 kJ mol −-− 1, while the electron gain enthalpy of BrBrBr is −-− 325.0 kJ mol −-− 1. Given the lattice enthalpy of NaBrNaBrNaBr is −-− 728.4 kJ mol −-− 1. The energy for the formation of NaBrNaBrNaBr ionic solid is (−-−) ‾×\underline{\hspace{2cm}}\times​× 10 −-− 1 kJ mol −-− 1.
Numerical answer
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