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Structure of Atom question

2019 · 9 Jan · Shift 1 · Q21
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Structure of Atom question

2019 · 9 Jan · Shift 1 · Q21

JEE MainChemistryStructure of AtomMCQ+4 / −1
The highest value of the calculated spin only magnetic moment (in BM) among all the transition metal complexes is :
  1. A
    5.92
  2. B
    6.93
  3. C
    3.87
  4. D
    4.90
View written solutionFree

Correct answer: A

  1. Spin-only magnetic moment formula

For a transition metal complex, the spin-only magnetic moment is

μ=n(n+2) BM\mu = \sqrt{n(n+2)}\ \text{BM}μ=n(n+2)​ BM

where nnn is the number of unpaired electrons.

  1. Find the maximum possible number of unpaired electrons

Among transition metal complexes, the maximum number of unpaired electrons occurs for a high-spin d5d^5d5 system.

This gives

n=5n=5n=5

  1. Calculate the magnetic moment

μ=5(5+2)=35\mu = \sqrt{5(5+2)} = \sqrt{35}μ=5(5+2)​=35​

μ≈5.92 BM\mu \approx 5.92\ \text{BM}μ≈5.92 BM

  1. Check the options
  • A: 5.925.925.92 ✅
  • B: 6.936.936.93 corresponds to more than 5 unpaired electrons, not possible for transition metal complexes
  • C: 3.873.873.87 corresponds to n=3n=3n=3
  • D: 4.904.904.90 corresponds to n=4n=4n=4

Therefore, the highest possible spin-only magnetic moment is

5.92 BM\boxed{5.92\ \text{BM}}5.92 BM​

So, Option A is correct.

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