JEE MainChemistryStructure of AtomMCQ+4 / −1
Which one of the following sets of ions represents the collection of isoelectronic species? (Atomic nos. : F = 9, Cl = 17, Na = 11, Mg = 12, Al = 13, K = 19, Ca = 20, Sc = 21)
- A, , ,
- B, , ,
- C, , ,
- D, , ,
View written solutionFree
Correct answer: C
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Isoelectronic species are atoms/ions having the same number of electrons.
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Let us calculate the number of electrons in each ion using: for cations, and for anions.
- Check each option:
Option A: , , ,
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Not all have the same number of electrons. So, A is incorrect.
Option B: , , ,
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Two ions have 10 electrons and two have 18 electrons. So, B is incorrect.
Option C: , , ,
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All have 18 electrons. So, C is correct.
Option D: , , ,
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Three ions have 10 electrons, but has 18 electrons. So, D is incorrect.
- Therefore, the collection of isoelectronic species is:
So, the correct option is:
- Comparison with stored correct answer: Stored correct answer = C
My derived answer = C
Hence, they agree.
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